4.9x^2+1x-3.8=0

Solution for 4.9x^2+1x-3.8=0 equation:

4.9x^2+1x-3.8=0

We add all the numbers together, and all the variables

4.9x^2+x-3.8=0

a = 4.9; b = 1; c = -3.8;
Δ = b2-4ac
Δ = 12-4·4.9·(-3.8)
Δ = 75.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{75.48}}{2*4.9}=\frac{-1-\sqrt{75.48}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{75.48}}{2*4.9}=\frac{-1+\sqrt{75.48}}{9.8}
$